In dividing a number by 585, a student employed the method of short division. He divided the number successively by 5,9 and 13 (factors of 585) and got the remainders, 4,8, 12 respectively.If he had divided the number by 585, what would have been the remainders?
Created: 6 years ago |
Updated: 2 years ago
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Let the number be x.
x is successively divided by 5, 9 and 13 (factors 585) and got the remainders 4, 8, 12 respectively.
Difference of all the divisors and remainders respectively is 1.
Divisor−Remainder = 1
5−4 = 1
9−8 = 1
13−12 = 1
Therefore; 585−Remainder = 1
Remainder = 585−1 = 584 (ans)
Md Azizur Rahman
Founder of Satt
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