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Question
if A B C D and E are points in a plane such that the line CD bisects angle ACb and line CB bisects right angle ACE ,then DCE=?
45 deg
22.5 deg
65.5 deg
85 deg
none
ANSWER : 3
Descrption
<p>Angle ACE = 90 degree since CB bisects ACE then BCE = 45 degree </p><p>ACB = 45 degree. </p><p>Since CD bisects ACB We get two angles ACD = 45/2 = 22.5 and DCB = 45/2 = 22.5 </p><p><img 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= DCB + BCE = 22.5 + 45 = 67.5</p>
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