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3
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রোধের একটি তারের মধ্যে দিয়ে 2A তড়িৎ 6 min ধরে প্রবাহিত হলে উৎপন্ন তাপের পরিমাণ কত?
1020.57 cal
1028.57 cal
1028 cal
1032 cal
ANSWER : 2
Descrption
<p style="margin-left:0px;"><strong>1028.57 cal</strong></p><p style="margin-left:0px;">তাপের পরিমাণ, Q = I^2Rt</p><p style="margin-left:0px;">I = 2 A R = 3 Ω t = 6 min = 6*60 s = 360 s</p><p style="margin-left:0px;">সুতরাং,</p><p>Q = (2^2)(3)(360) </p><p>Q = 1028.57 cal </p><p style="margin-left:0px;">অতএব, উৎপন্ন তাপের পরিমাণ হল 1028.57 cal।</p>
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