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Question
একটি কণার উপর
T
→
=
(
5
i
^
-
3
j
^
-
2
k
^
)
N
বল প্রয়োগে কণাটির
r
→
=
(
3
i
^
+
2
j
^
+
k
^
)
m
সরণ হয় । সম্পাদিত কাজের পরিমাণ কত ?
5 J
2 J
7 J
8 J
ANSWER : 3
Descrption
<p style="margin-left:0px;"><strong>7 J</strong>।</p><p style="margin-left:0px;">কাজের সংজ্ঞা অনুসারে,</p><p>W = F * s * cos θ </p><p style="margin-left:0px;">যেখানে,</p><ul><li>W হল কাজ</li><li>F হল বল</li><li>s হল সরণ</li><li>θ হল বল এবং সরণের মধ্যবর্তী কোণ</li></ul><p style="margin-left:0px;">এখানে,</p><ul><li>F = (5ˆi - 3ˆj - 2ˆk) N</li><li>s = (3ˆi + 2ˆj + ˆk) m</li><li>θ = 0°</li></ul><p style="margin-left:0px;">সুতরাং,</p><p>W = (5ˆi - 3ˆj - 2ˆk) N * (3ˆi + 2ˆj + ˆk) m * cos 0° </p><p style="margin-left:0px;">= 5ˆi * 3ˆi + 5ˆi * 2ˆj + 5ˆi * ˆk - 3ˆj * 3ˆi - 3ˆj * 2ˆj - 3ˆj * ˆk - 2ˆk * 3ˆi - 2ˆk * 2ˆj - 2ˆk * ˆk</p><p>= 15 + 10 - 2 - 9 - 6 - 4 - 6 - 4 </p><p>= 7 J </p><p style="margin-left:0px;">অতএব, সম্পাদিত কাজের পরিমাণ হল <strong>7 J</strong>।</p>
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