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Question
A train which travels at a uniform speed due to some mechanical fault after traveling for an hour goes at 3/5th of the original speed and reached the destination 2 hours late. If the fault had occurred after traveling another 50 miles, the train would ha
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ANSWER : 2
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<p><span style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff;">Let, the original speed is x and 3/5 th of original speed is 0.6x</span><br style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff; outline: none; box - sizing: border - box;" /><br style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff; outline: none; box - sizing: border - box;" /><span style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff;">50/0.6x - 50/x = 40/60</span><br style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff; outline: none; box - sizing: border - box;" /><span style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff;">(250 - 150)/3x = 2/3</span><br style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff; outline: none; box - sizing: border - box;" /><span style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff;">100/3x = 2/3</span><br style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff; outline: none; box - sizing: border - box;" /><span style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff;">6x = 300</span><br style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff; outline: none; box - sizing: border - box;" /><span style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff;">x = 50</span><br style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff; outline: none; box - sizing: border - box;" /><br style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff; outline: none; box - sizing: border - box;" /><span style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff;">3/5 of 50 = 30</span><br style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff; outline: none; box - sizing: border - box;" /><span style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff;">speed reduces by = 50 - 30 = 20</span><br style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff; outline: none; box - sizing: border - box;" /><span style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff;">It is late by 2 hours and by this time it goes 30*2 = 60</span><br style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff; outline: none; box - sizing: border - box;" /><span style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff;">If the train goes with its original speed it took 60/20 = 3 hours after the first hour. That means total 4 hours.</span><br style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff; outline: none; box - sizing: border - box;" /><span style = "font - family: 'Open Sans', Arial, sans - serif; font - size: 15.73px; background - color: #ffffff;">Therefore, total distance covered </span></p>
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