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Question
A sum of money amounts to Tk. 6690 after 3 years and to TK. 10035 after 6 years on compound interest . Find the sum.
TK. 4360
TK. 4560
TK. 4660
TK. 4460
ANSWER : 4
Descrption
<pre> In 6 years sum with compound interest P(1 + <math xmlns = "http://www.w3.org/1998/Math/MathML"><mfrac><mi>r</mi><mn>100</mn></mfrac><msup><mo>)</mo><mn>6</mn></msup><mo> = </mo><mn>10035</mn><mo> </mo><mo>.</mo><mo>.</mo><mo>.</mo><mo>.</mo><mo> </mo><mo>(</mo><mi>i</mi><mo>)</mo><mo> </mo><mspace linebreak = "newline"/><mi>i</mi><mi>n</mi><mo> </mo><mn>3</mn><mo> </mo><mi>y</mi><mi>e</mi><mi>a</mi><mi>r</mi><mo> </mo><mo>,</mo><mo> </mo><mi>s</mi><mi>u</mi><mi>m</mi><mo> </mo><mi>w</mi><mi>i</mi><mi>t</mi><mi>h</mi><mo> </mo><mspace linebreak = "newline"/><mi>c</mi><mi>o</mi><mi>m</mi><mi>p</mi><mi>o</mi><mi>u</mi><mi>n</mi><mi>d</mi><mo> </mo><mi>i</mi><mi>n</mi><mi>t</mi><mi>e</mi><mi>r</mi><mi>e</mi><mi>s</mi><mi>t</mi><mspace linebreak = "newline"/><mi>P</mi><mo>(</mo><mn>1</mn><mo> </mo><mo> + </mo><mo> </mo><mfrac><mi>r</mi><mn>100</mn></mfrac><msup><mo>)</mo><mn>3</mn></msup><mo> = </mo><mn>6690</mn><mo>.</mo><mo>.</mo><mo>.</mo><mo>.</mo><mo>(</mo><mi>i</mi><mi>i</mi><mo>)</mo><mspace linebreak = "newline"/><mo>(</mo><mi>i</mi><mo>)</mo><mo>÷</mo><mo>(</mo><mi>i</mi><mi>i</mi><mo>)</mo><mspace linebreak = "newline"/><mo>⇒</mo><mfrac><mrow><mi>P</mi><mo>(</mo><mn>1</mn><mo> + </mo><mstyle displaystyle = "true"><mfrac><mi>r</mi><mn>100</mn></mfrac></mstyle><msup><mo>)</mo><mn>6</mn></msup></mrow><mrow><mi>P</mi><mo>(</mo><mn>1</mn><mo> + </mo><mstyle displaystyle = "true"><mfrac><mi>r</mi><mn>100</mn></mfrac></mstyle><msup><mo>)</mo><mn>3</mn></msup></mrow></mfrac><mo> = </mo><mfrac><mn>10035</mn><mn>6690</mn></mfrac><mspace linebreak = "newline"/><mo>.</mo><mo>'</mo><mo>.</mo><mo> </mo><mo>(</mo><mn>1</mn><mo> + </mo><mfrac><mi>r</mi><mn>100</mn></mfrac><msup><mo>)</mo><mn>3</mn></msup><mo> = </mo><mfrac><mn>3</mn><mn>2</mn></mfrac><mspace linebreak = "newline"/><mo>(</mo><mi>i</mi><mi>i</mi><mo>)</mo><mo>⇒</mo><mi>P</mi><mo>×</mo><mfrac><mn>3</mn><mn>2</mn></mfrac><mo> = </mo><mn>6690</mn><mspace linebreak = "newline"/><mo>⇒</mo><mi>p</mi><mo> = </mo><mfrac><mrow><mn>6690</mn><mo>×</mo><mn>2</mn></mrow><mn>3</mn></mfrac><mspace linebreak = "newline"/><mo>.</mo><mo>'</mo><mo>.</mo><mo> </mo><mi>P</mi><mo> = </mo><mn>4460</mn><mo> </mo></math> </pre>
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