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ax+by+c=0 এবং

a_{1} x + b_{1} y + c_{1} = 0

রেখাদ্বয় পরস্পরের উপর লম্ব হলে নিম্নের কোনটি সত্য?

a b_{1} - a_{1} b = 0

a b - a_{1} b_{1} = 0

a a_{1} + b b_{1} = 0

a a_{1} - b b_{1} = 0

ANSWER : 3

Descrption

সরলরেখা লম্ব হওয়ার শর্ত m1 x m2 = -1ax+by+c=0………(i)=&gt;&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi mathvariant="normal">m</mi><mn>1</mn></msub><mo>=</mo><mo>-</mo><mfrac><mi mathvariant="normal">a</mi><mi mathvariant="normal">b</mi></mfrac></math>and, a1 x+ b1 y + c = 0 ……………….(ii)=&gt;&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>m</mi><mn>2</mn></msub><mo>=</mo><mo>-</mo><mfrac><msub><mi>a</mi><mn>1</mn></msub><msub><mi>b</mi><mn>1</mn></msub></mfrac></math>now, &nbsp; &nbsp;m1 x m2 = -1=&gt;&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mo>-</mo><mfrac><mi>a</mi><mi>b</mi></mfrac><mo>×</mo><mo>-</mo><mfrac><msub><mi>a</mi><mn>1</mn></msub><msub><mi>b</mi><mn>1</mn></msub></mfrac><mo>=</mo><mo>-</mo><mn>1</mn></math>=&gt; aa1 + bb1 = 0 &nbsp; &nbsp; (Proved)&nbsp; &nbsp;

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