R is list of 15 consecutive integers, and T is a list of 21 consecutive integers. The median of the integers in list R is equal to the least integer in list. Combined lists are combined into one th of 36 integers, how many different integers are on the combined list?
(Number Concept)

Created: 1 year ago | Updated: 1 year ago

Updated: 1 year ago

$A s, R c o n t a i n s 15 c o n s e c u t i v e i n t e g e r s, t h e n l i s t o f R m a y b e :$

R - 7, R - 6, R - 5, R - 4, R - 3, R - 2, R - 1

R + 1, R + 2, R + 3, R + 4, R + 5, R + 6, R + 7

Here, R = Median

$A g a i n, A s T c o n t a i n s 21 c o n s e c u t i v e i n t e g e r s, t h e n l i s t o f T m a y b e$

R + 1, R + 2, R + 3, R + 4, R + 5 . R + 6 . R + 7

R + 8 R + 9 R + 10 R + 11 R + 12, R + 13, R + 14, R + 15, R + 16, R + 17, R + 18

R + 19, R + 20

$H e r e, A s t h e m e d i a n o f t h e i n t e g e r s i n l i s t R i s e q u a l t o t h e l e a s t i n t e g e r i n l i s t T (A s R = R) .$

$N o w, i f t h e t w o l i s t s a r e c o m b i n e d i n t o o n e l i s t o f 36$

$I n t e g e r s, t h e n u m b e r o f d i f f e r e n t i n t e g e r s a r e o n t h e$

$C o m b i n e d l i s t a r e = 36 - 8 (A s, R, R + 1, R + 2, R + 3, R + 4, R + 5, R + 6, R + a r e s a m e n u m b e r s)$

1 year ago

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