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Solve the following mathematical problems:

Twice the width of a rectangle is 10 meters more the its length. If the area of the region enclosed by the rectangle is 600 square meters , then find its perimeter. (Geometry (Rectangle))

Created: 2 years ago | Updated: 1 year ago
Updated: 1 year ago
Answer :

Let, the length of the rectangle is x meter 

And the width of the rectangle is y meter

According to question,

2y=x+10 

Since width cannot be (-)ve. So we find y=20

That means the width of the rectangle is 20 meters

The length of the rectangle is x=600y 

x=60020=30

The length of the rectangle is 30 meters.

 The perimeter of the rectangle =  2× (30+20) = 2×50=100 meters. 

ans. The perimeter is 100m. 

1 year ago

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