মান নির্ণয় কর : $\int_{0}^{1} \frac{\sin^{- 1} x}{\sqrt{1 - x^{2}}} d x$

Created: 1 year ago | Updated: 1 year ago

Updated: 1 year ago

ধরি, $\sin^{- 1} x = z$

$∴ \frac{1}{\sqrt{1 - x^{2}}} dx = dz$

$x = 1$ হলে $z = \frac{π}{2}$

$x = 0$ হলে $z = 0$

এখন, $\int_{0}^{1} \frac{\sin^{- 1} x}{\sqrt{1 - x^{2}}} d x$

$= \int_{0}^{π / 2} z d z = {[\frac{z^{2}}{2}]}^{π / 2} = (\frac{{(\frac{π}{2})}^{2}}{2} - \frac{0}{2}) = \frac{π^{2}}{8}$ $(Ans)$

1 year ago

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