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3x+2+x-1x-5=2 ⇒3x-5+x-1x+2x+2x-5=2⇒3x-15+x2+2x-x-2x2-5x+2x-10=2⇒x2+4x-17x2-3x-10=2⇒2x2-6x-20=x2+4x-17⇒x2-10x-3=0Now using ax2+bx+c=0Here, a=1;b=-10;c=-3We know, x=-b±b2-4ac2ax=--10±-102-4×1×-32×1⇒x=10±100+122⇒x=10±1122⇒x=10±16×72⇒x=10±472⇒x=25±272∴x=5±27
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