or
or
Two men X and Y started working for a certain company at similar jobs on January 1, 1950. X asked for an initial salary of Rs. 300 with an annual increment of Rs. 30. Y asked for n initial salary of Rs. 200 with a rise of Rs. 15 every six months. Assume that the arrangements remained unaltered till December 31, 1959. Salary is paid on the last day of the month. What is the total amount paid to them as salary during the period?
Initial annual salary of X = 12 300 = 3600 Tk.
Annual increment of X = 12 30 = 360 Tk.
Total salary of X for 10 years will be found using arithmetic progression,
with initial values 3,600 Tk. and difference 360 Tk. for 10 years.
So, here n = 10; a = 3600; d = 360
Total salary of X =
=5{(7200+(9
Initial half-yearly of Y = 6 200 = 1, 200Tk
and half-yearly salary of Y = 15 6 = 90Tk
Total salary of Y for 10 years or 20 half-yearly period will be found using arithmetic progression
with initial value Tk. 1,200 and difference Tk. 90 for 20 half-year period
So, here n = 20 a = 1, 200 d = 90
Total salary of Y =
