P=(x: x²-9-0}, Q= {x:x²+x-6=0} হলে P ∩ Q = কত?

Created: 1 year ago | Updated: 1 year ago

Updated: 1 year ago

{-3,2,3}

{-3}

{2}

{3}

নবম-দশম শ্রেণি (মাধ্যমিক) উচ্চতর গণিত সেট ও ফাংশন

Des

238

প্রশ্ন:
P=(x: x²-9-0}, Q= {x:x²+x-6=0} হলে P ∩ Q = কত?

সঠিক উত্তর : {-3}

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Des.

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Content

P=(x: x²-9-0}, Q= {x:x²+x-6=0} হলে P ∩ Q = কত?

প্রশ্ন:
P=(x: x²-9-0}, Q= {x:x²+x-6=0} হলে P ∩ Q = কত?

উচ্চতর গণিত

Related Question

Related Question

Promotion

P=(x: x2-9-0}, Q= {x:x²+x-6=0} হলে P ∩ Q = কত?

প্রশ্ন: P=(x: x2-9-0}, Q= {x:x²+x-6=0} হলে P ∩ Q = কত?

উচ্চতর গণিত

Related Question

Related Question

Promotion

P=(x: x²-9-0}, Q= {x:x²+x-6=0} হলে P ∩ Q = কত?

প্রশ্ন:
P=(x: x²-9-0}, Q= {x:x²+x-6=0} হলে P ∩ Q = কত?