or
or
ax+by-c= 0
ax+by= c
x/(c/a)+y/(c/b)= 1
ত্রিভুজের ক্ষেত্রফল : ½×ভূমি×উচ্চতা
= ½×(c/a)×(c/b)
= c2/2ab
ax+by-c=0 - - - (1)
Putting x=0 in (1) we get, by=c or, y=c/b
Putting y=0 in (1) we get, ax=c or, x=c/a
So, area of the triangle formed by the straight line (1) with x-axis and y-axis = ½c/b*c/a = c^2/2ab
