log3 × log2 × log3X = 0
Created: 2 years ago
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Updated: 4 months ago
log3 × log2 × log3X = 0
log3[log2(log3X)]=0
log2(log3X)=30 [ logaX = b, => X= ab ]
log2(log3X)=1 [ log3= log, X= log2(log3X)] logX
log2(log3X)
Log3x= 21
Log3x= 2
X= 32
X=9
Asked by
Faijul Islam
Faijul Islam