log3​ × log2 × log3X = 0

Created: 2 years ago | Updated: 4 months ago

log3​ × log2 × log3X  = 0

log3​[log2(log3X)]=0

log2​(log3X)=3 [ logaX = b, => X= ab ]

log2​(log3X)=1 [ log3= log, X= log2(log3X)] logX

log2​(log3X)

Log3x= 21

Log3x= 2

X= 32

X=9

 

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