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Find V_ab and Is.

Created: 3 weeks ago | Updated: 3 weeks ago

Updated: 3 weeks ago

$V_{a} = \frac{R_{4}}{R_{3} + R_{4}} E = \frac{2}{6 + 2} \times 12 = 3 V$

$V_{b} = \frac{R_{2}}{R_{1} + R_{2}} E = \frac{3}{5 + 3} \times 12 = 4.5 V$

$V_{a b} = V_{a} - V_{b} = 3 - 4.5 = - 1.5 V$

$I_{s} = I_{1} + I_{3} = \frac{V_{b}}{3} + \frac{V_{a}}{2} = \frac{4.5}{3} + \frac{3}{2} = 3 A$

3 weeks ago

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Bangladesh Chemical Industries Corporation (BCIC) || Sub-Assistant Engineer (EEE) (14-02-2025) ইলেকট্রিক্যাল এন্ড ইলেকট্রনিক্স ইঞ্জিনিয়ারিং (EEE)

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ইলেকট্রিক্যাল এন্ড ইলেকট্রনিক্স ইঞ্জিনিয়ারিং (EEE)

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