A 400 V DC motor takes an armature current of 100 A when its speed is 1000 rpm. If the armature resistance is 0.25 ohm, calculate the torque produced in Nm.
Created: 3 weeks ago |
Updated: 3 weeks ago
Updated: 3 weeks ago
Given,
Terminal Voltage, Vt = 400V Speed, N = 1000 r. p. m. = (1000 = 16.667 r. p.s.
Angular speed, = = 104.72 rad/sec
Armature Resistance,
Armature current = 100A
Back emf = Eb
Electrical Power Converted to mechanical power = Pm