A 108 MHz carrier is frequency modulated by a 10 kHz sine wave with a frequency deviation of 50 kHz. Determine the modulation index, the highest and lowest instantaneous frequencies of the FM wave.

Created: 3 weeks ago | Updated: 3 weeks ago

Updated: 3 weeks ago

Modulation index for FM,

$m_{\int} = \frac{∆ \int}{\int_{m}} = \frac{50}{10} = 5$

The highest instantaneous frequency, $\int_{m a x} = \int_{c} + ∆ \int = 108 + 0.1 = 108.1 M H z$ Ans

The lowest instantaneous frequency, $\int_{m i n} = \int_{c} - ∆ \int = 108 - 01 = 107.9 M H z$ Ans

3 weeks ago

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