LCM of 2 and 3 is 6
Work done in first 6 days = (630+315+210)=6+6+630=1830=415
Remaining work = (1-35)=(5-35)=25
Next 3 days work done by them= (330+115+110)=3+2+330=830=415
Remaining work after 9 days = (25-415)=(6-415)=215
In 10th days, B will help A, thus work done by them after 9 days= (130+115)=1+230=330=110
Remaining work= (215-110)=(4-330)=130
In 11th days, A alone can do 13 part of work which is the amount of remaining work.
Total 11 days will be required to complete the whole work. ans.