Solve the following mathematical problems:
A basin can be filled by tap A in 5 hours and tap B in 8 hours, each tap working on its own When the basin in full and a drainage hole is open, the water is drained in 20 hours. If initially the basin was empty and someone started the two taps together but left the drainage hole open, how long does it take for the basin to be filled?
(Pipe & Cistern)Basin is filled by Ain 5 hours
∴In 1 hour, part of Basin is filled
Similarly by ‘ B’ in 1 hour, part of Basin is filled
The both tap can fill in 1 hour = part of Basin
As, the leak can empty the fill Basin in 20 hours
In 1 hour, the leak can empty part of Basin.
The amount of water remain in the Basin in 1 hour= part of Basin
Thus, while two taps are working,
of the Basin is filled in = 1 hour
1 or full part of the Basin is filled n = hour