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Solve the following mathematical problems:

A basin can be filled by tap A in 5 hours and tap B in 8 hours, each tap working on its own When the basin in full and a drainage hole is open, the water is drained in 20 hours. If initially the basin was empty and someone started the two taps together but left the drainage hole open, how long does it take for the basin to be filled?

(Pipe & Cistern)

Created: 2 years ago | Updated: 1 year ago
Updated: 1 year ago
Answer :

Basin is filled by Ain 5 hours

In 1 hour, 15part of Basin is filled

Similarly by ‘ B’ in 1 hour, 18 part of Basin is filled

The both tap can fill in 1 hour =15+18=8+540=1340 part of Basin

As, the leak can empty the fill Basin in 20 hours

 In 1 hour, the leak can empty 120 part of Basin.

The amount of water remain in the Basin in 1 hour=1340-120=13-240=1140 part of Basin

Thus, while two taps are working,

1140 of the Basin is filled in = 1 hour

 1 or full part of the Basin is filled n = 1×4011=4011=3711 hour

1 year ago

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