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Question
A worker was hired for 7 days. Each day, he was paid Tk. 10 more than what he was paid for the previous day of work. The total amount he was paid in the first 4 days of work equaled the total amount he was paid in the last 3 days. What was his starting pay?
Tk. 90
Tk. 138
Tk. 153
Tk. 160
Tk. 163
ANSWER : 1
Descrption
<p>Let, the first day pay be x</p> <p>1st day = x</p> <p>2nd day = x + 20</p> <p>3rd day = x + 30</p> <p>4th day = x + 30</p> <p>Total = x + x + 10 + x + 20 + x + 30 = 4x + 60</p> <p>5th day = x + 40</p> <p>6th day = x + 50</p> <p>7th day = x + 60</p> <p>Total = x + 40 + x + 50 + x + 60 = 3x + 150</p> <p>4x + 60 = 3x + 150</p> <p>x = 90</p>
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