শতকরা কতজন প্রোগ্রাম  A, B, C

Let, x number of students have more than 5 less than 9 marbles

Now, required condition is 5

10 students have less than 6 marbles: means at least 10 students have 5 marbles

4 students have more than 8 marbles: means 4 students have at least 9 marbles. 

Therefore, number of students have more 5 less than 9 marbles=25-(10+4)= 11 ans.

Repeat: Rupali Bank Ltd. (Officer - Cash) 2018

Given, total students = 70

M=40; P= 35; C = 30  [Using first alphabet of all subjects]

P+C+M=15

Now, we can solve it by using Venn diagram. Let depict it.

We let the number of students

who study exactly two subjects are x, y & z. 

We have to find out the value of (x + y + z)

According to the question

$$\begin{gathered} 40-15-x-y+35-15-x-z+30-15-y-z+x+y+z+15=70 \\ \Rightarrow 105-30-x-y-z=70 \\ \Rightarrow 75-70=x+y+z \\ x+y+z=5 \end{gathered}$$
The number of students studying exactly two subjects is 5. 

প্রশ্নে বলা হচ্ছে, একটি শ্রেণির 40% ছাত্র পরিসংখ্যানে এবং 35% ছাত্র কম্পিউটারে ফেল করলো। শ্রেণিতে মোট 200 জন শিক্ষার্থী আছে এবং 70 জন কোনো বিষয়েই ফেল করেনি। কতজন শিক্ষার্থী উভয় বিষয়েই ফেল করেছে?

Number of students failed in statistics $= 200 \times 40\% = 80$

∴ Number of students passed in statistics = 200 - 80 = 120

Again,

Number of students failed in Computer $= 200 \times 35\% = 70$

∴ Number of students passed in Computer = 200 - 70 = 130

Given, passed in both subjects = 70

∴  Number of students passed in one or both subjects = 120+ 130-70 = 180

∴  Number of students failed in both subject = 200 - 180 = 20