$As, R contains 15 consecutive integers, then list of R may be:$

                                                                                                                                                        R

Here, R = Median

$Again, As T contains 21 consecutive integers, then list of T may be$

$Here, As the median of the integers in list R is equal to the least integer in list T (As R = R ).$

$Now, if the two lists are combined into one list of 36$

$Integers, the number of different integers are on the$

$Combined list are = 36-8 (As, R, R + 1, R + 2, R + 3, R + 4, R + 5, R + 6 ,R+ are same numbers)$

$Let, the number of total cars is 60$

$Whereas, the number of black cars is 30$

$And the number of blue cars is 10$

$And the number of silver cars is 10$

$And the number of white cars is 10$

$\therefore Total car initially = 30 + 10 + 10 + 10 = 60$

$$\begin{gathered} During the next month, \\ Black cars sold 70\% of 30=21 \end{gathered}$$

$$\begin{gathered} \therefore Blue cars sold 80\% of 10=8 \\ \therefore Silver cars sold 30\% of 10=3 \end{gathered}$$

$$\begin{gathered} \therefore White cars sold 40\% of 10 = 4 \\ \therefore The number of sold cars = 21+8+3+4=36 \end{gathered}$$

$\therefore The percentage of cars in the shipment were sold during that month=(\frac{36}{60}\times 100)\%=60\%$

Answer: 60%

$If the lemon candies are removed,$

$Then 85\% of the original number of candies will remain.$

$Among them, the fraction of lime candies will be=\frac{25}{85}=\frac{5}{17}$

$Answer: \frac{5}{17}$