R is list of 15 consecutive integers, and T is a list of 21 consecutive integers. The median of the integers in list R is equal to the least integer in list. Combined lists are combined into one th of 36 integers, how many different integers are on the combined list?

$As, R contains 15 consecutive integers, then list of R may be:$

                                                                                                                                                        R

Here, R = Median

$Again, As T contains 21 consecutive integers, then list of T may be$

$Here, As the median of the integers in list R is equal to the least integer in list T (As R = R ).$

$Now, if the two lists are combined into one list of 36$

$Integers, the number of different integers are on the$

$Combined list are = 36-8 (As, R, R + 1, R + 2, R + 3, R + 4, R + 5, R + 6 ,R+ are same numbers)$