The pressure difference between gauges in a piping network is measured 0.2 kg/cm2. If the friction factor is 0.002, determine the flow rate at outlet.

আমরা জানি, 

মোট হেডলস  $H_T - \frac{0.2\times {10}^4}{1000}-2m of H_{2}O$

For parallel pipe $H_T -H_1 - H_2$

আবার, 

Headloss for pipe I  -$\frac{fL Q_1^2}{12D^5}$

বা, $2=\frac{0.002\times 500\times Q_2^1}{12\times 0.5^5}$

$\therefore Q_1 -0.87 m^3/Sce$

1 Headloss for pipe 2 = $\frac{fL Q_2^2}{12D^5}$

বা, $2=\frac{0.002\times 600\times Q_2^2}{12\times 0.3^5}$

$\therefore Q_1 -0.22 m^3/Sce$

$\therefore$ আউটলেটের নির্গমন  $Q=Q_1+Q_2=0.87+0.22=1.09 m^3/sce$