Write a function which receives an array of integers as parameter and print the numbers divisible by 3 in the array.

Resolution=Voltage Range​/2^n

Where:

• Voltage Range = 3.3V (the output voltage range from 0V to 3.3V)
• n = number of bits in the digital input (12 bits in this case)

Now, let's calculate the resolution:

Resolution = 3.3/2^12 
                  ​=0.80586mV

So, the resolution of the analogue output is approximately 0.80586 mV per bit.

Conditions for deadlock

For a deadlock to occur, all four of the following conditions must be met simultaneously:

Mutual Exclusion: At least one resource must be held in a non-sharable mode; only one process can use the resource at any given time.

Hold and Wait: A process must be holding at least one resource and waiting to acquire additional resources that are currently being held by other processes.

No Preemption: Resources cannot be forcibly taken away from a process that is holding them. They must be released voluntarily by the process.

Circular Wait: A set of processes must exist such that each process in the set is waiting for a resource held by the next process in the set, forming a closed chain.

Deadlock with a single process

No, it is not possible to have a deadlock involving only a single process.

The "circular wait" condition requires at least two processes. A deadlock is a "circular" dependency where process P1 waits for a resource held by P2, and P2 waits for a resource held by P1.

With only one process, there is no "other process" for it to wait on, so the circular wait condition is not met. This makes a deadlock impossible, even if the single process is holding one resource and waiting for another.