পড়ন্ত কোনো বস্তু 5 সেকেন্ডে কত দূরত্ব অতিক্রম করবে?
Created: 1 year ago |
Updated: 7 months ago
best ans
Formula of total distance of lawing object
S=ut+(1÷2)×g×(2t-1)
u=0
g=9.8 m/s^2
t=5th s
S=0+(1÷2)×9.8×(2×5-1)
=44.1 m
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