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Question
140 Ib ভরের একজন লোক দৌড়াইয়া 3.8 sec এ 11 ft খাড়া পথ অতিক্রম করে উপর তলায় উঠল, তার ব্যয়িত ক্ষমতা কত?
0.5691 HP
0.7369 HP
1.5691 HP
1.7369 HP
ANSWER : 2
Descrption
<p>we know that, p = w / t</p><p>Here w = m×g×h</p><p>m=140 lb =( 140×0.454) kg = 63.5 Kg</p><p>g= 9.8 m/s<sup>2</sup></p><p>h= 11 ft=3.35 m</p><p>So, w = 63.5×9.8×3.35=2086.705 kg/ms<sup>2</sup> = 2084.705 N</p><p>Now, P= 2086.705 /3.8 W = 549.125 W</p><p>Hence, p= 549.125/746 HP =0.7369 HP</p>
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