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H = \frac{v^{2} 0 \sin θ}{2 g}

H_{m a x} = \frac{{v^{2}}_{0} \sin θ_{0}}{2 g}

H_{} = \frac{2 {v^{2}}_{0}}{2 g}

H = \frac{v_{0} \cos θ}{g}

H = \frac{v_{0} \cos^{2} θ}{2 g}

ANS : 2

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