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Question
10kg ভরের একটি বন্দুক হতে 5gm ভরের একটি গুলি যদি 200ms-1বেগে বের হয়ে যায় তবে বন্দুকের পশ্চাৎ বেগ কত?
10cms-1
20cms-1
25cms-1
50cms-1
ANSWER : 1
Descrption
<p> আমরা জানি,</p><p> MV = - mv</p><p>এখানে,</p><p>M= বন্দুকের ভর = 10kg</p><p>V=বন্দুকের বেগ= ?</p><p>m = গুলির ভর= 5gm = ( 5/1000)kg = 0.005 kg</p><p>v = গুলির বেগ = 200 ms-1</p><p> এখন,</p><p> MV = - mv</p><p> বা, V = - mv / M</p><p> বা, V = - (0.005 x 200)/10</p><p> বা , V = - 0.1 ms-1</p><p> = V = - 10 cms-1</p>
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