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cot

θ

\sqrt{3} = 2 \cos e c θ

সমীকরণের সমাধান -

\sqrt{3} = 2 \cos e c θ

=2n

π

\frac{π}{3}

θ = 2 n π + \frac{π}{3}

θ = 2 nπ + \frac{π}{6}

θ = 2 nπ - \frac{π}{6}

ANS : 2

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