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C o s θ + \sqrt{3} \sin θ = 2

সমীকরণের সাধারণ সমাধান -

θ = 2 n π - \frac{π}{3}

θ = 2 nπ + \frac{π}{6}

θ = 2 nπ + \frac{π}{3}

θ = 2 nπ - \frac{π}{4}

ANS : 3

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