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y = \frac{\sqrt{x} + 1}{\sqrt{x} - 1}

\frac{d y}{d x} = ?

\frac{1}{\sqrt{x} (\sqrt{x} + 1)^{2}}

\frac{1}{\sqrt{x} (\sqrt{x} + 1)^{2}}

\frac{1}{\sqrt{x} (\sqrt{x} + 1)^{2}}

\frac{- 1}{\sqrt{x (\sqrt{x} - 1)^{2}}}

ANS : 4

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