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0. 125 M HCl এসিডের 500 মি.লি. দ্রবণকে 0.100 M লঘু দ্রবণে পরিণত করতে কতটুকু পানি যোগ করতে হবে?
100 mL
150 mL
125 mL
75 mL
ANSWER : 3
Descrption
<p>S<sub>2</sub>V<sub>2</sub> = S<sub>1</sub>V<sub>1</sub> → V<sub>2</sub> = (0.125×500)/0.1 = 625 mL </p><p>যোগ করব = (625—500) = 125 mL</p>
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