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Question
How many terms are there in 20, 25, 30......140?
22
25
23
24
ANSWER : 2
Descrption
<p style="margin-left:0px;">To find the number of terms in the sequence 20, 25, 30, ..., 140, we can use the formula for the nth term of an arithmetic progression:</p><p style="margin-left:0px;">nth term (Tn) = a + (n - 1) * d</p><p style="margin-left:0px;">Where:</p><ul><li>a is the first term of the sequence (a = 20 in this case).</li><li>d is the common difference between consecutive terms (d = 25 - 20 = 5 in this case).</li><li>n is the number of terms we want to find.</li></ul><p style="margin-left:0px;">We need to find the value of n when Tn is equal to 140, as that's the last term in the sequence.</p><p style="margin-left:0px;">140 = 20 + (n - 1) * 5</p><p style="margin-left:0px;">Now, solve for n:</p><p style="margin-left:0px;">140 - 20 = (n - 1) * 5 120 = (n - 1) * 5</p><p style="margin-left:0px;">Divide both sides by 5:</p><p style="margin-left:0px;">120/5 = (n - 1) 24 = n - 1</p><p style="margin-left:0px;">Now, add 1 to both sides:</p><p style="margin-left:0px;">n = 24 + 1 n = 25</p><p style="margin-left:0px;">So, there are 25 terms in the sequence 20, 25, 30, ..., 140. The correct answer is 25.</p>
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