Edit Description

Fill up the form and submit

Question

A cricketer whose bowling average is 12.4 runs per wicket takes 5 wickets for 26 runs and thereby decreases his average by 0.4. The number of wickets taken by him till the last match was-

ANSWER : 4

Descrption

Let&nbsp;the number of wickets taken by bowler after the match be N.So, number of runs given by bowler after match =(N−5)×12.4 +26&nbsp;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;=12.4N−62+26&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;=12.4N−36Average of bowler after match =<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mi mathvariant="normal">N</mi><mn>12</mn><mo>.</mo><mn>4</mn><mi mathvariant="normal">N</mi><mo>−</mo><mn>36</mn><mo></mo></mrow><mi mathvariant="normal">N</mi></mfrac></math>As per question , average of bowler after match =12.4−0.4=12Equating both averages , we get&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mi mathvariant="normal">N</mi><mo>&nbsp;</mo><mn>12</mn><mo>.</mo><mn>4</mn><mi mathvariant="normal">N</mi><mo>−</mo><mn>36</mn></mrow><mi mathvariant="normal">N</mi></mfrac></math>&nbsp;= 12&nbsp; &nbsp;12.4N−12N = 36N =&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>36</mn><mrow><mn>0</mn><mo>.</mo><mn>4</mn></mrow></mfrac></math>N=90So, Number of wickets taken by bowler till last match =N−5=90−5=85

Please, login first. click here to login

Cancel Login

Edit Description

Question

Download Our Mobile Apps

Satt policy

Main Features

Subscribe our newsletter