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Question
একটি গাড়ি 54 Km/h আদিবেগ থেকে
2
m
/
s
2
সমমন্দনে কত সময় পর থামবে?
4.0 s
7.5 s
15. 0 s
6.0s
ANSWER : 2
Descrption
<p style="margin-left:0px;">গাড়ির আদিবেগ, v = 54 Km/h = 54000 m / 3600 s = 15 m/s গাড়ির ত্বরণ, a = -2 m/s^2 (-ve ত্বরণ মানে থামার দিকে) গাড়ির চূড়ান্ত বেগ, v_f = 0</p><p style="margin-left:0px;">গাড়ির থামার সময়, t নির্ণয়ের জন্য নিম্নলিখিত সমীকরণ ব্যবহার করা হয়:</p><p>v_f = v_i + at </p><p>0 = 15 m/s + (-2 m/s^2)t </p><p>2 m/s^2 t = 15 m/s </p><p>t = 15 m/s / 2 m/s^2 </p><p>t = 7.5 s </p><p style="margin-left:0px;">অতএব, গাড়িটি 7.5 সেকেন্ড পর থামবে।</p>
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