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Question
একটি পাথর 160 ft/sec আদিবেগে উপরের দিকে নিক্ষেপ করা হল। t সময়ে এর গতির সমীকরণ s =
160
t
-
16
t
2
হলে ভূমি হতে 256 ft উপরে পাথরটির বেগ কত?
48 ft/sec
96 ft /sec
120 ft /sec
160 ft /sec
ANSWER : 2
Descrption
<p style="margin-left:0px;"><strong>96 ft/sec</strong>।</p><p style="margin-left:0px;">প্রদত্ত সমীকরণটি একটি দ্বিঘাত সমীকরণ।</p><p style="margin-left:0px;">এখানে,</p><ul><li>s হল পাথরের উচ্চতা</li><li>t হল সময়</li><li>160 হল পাথরের আদিবেগ</li><li>-16 হল অভিকর্ষজ ত্বরণ</li></ul><p style="margin-left:0px;">256 ft উচ্চতায়,</p><p>s = 256 </p><p>160t - 16t^2 = 256 </p><p>16t^2 - 160t + 256 = 0 </p><p>(4t - 16)(4t - 16) = 0 </p><p>t = 16 </p><p style="margin-left:0px;">সুতরাং, 256 ft উচ্চতায়, পাথরের বেগ,</p><p>v = v_y = -160t + 160 </p><p>= -160 * 16 + 160 </p><p>= -2560 + 160 </p><p>= 96 ft/sec </p><p style="margin-left:0px;">অতএব, উত্তর হল <strong>96 ft/sec</strong>।</p>
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