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$y = \tan^{- 1} (\frac{2 x}{1 - x^{2}})$ হলে $\frac{d y}{d x}$ =কত?

- \frac{2}{1 + x^{2}}

\frac{2}{1 + x^{2}}

\frac{1}{1 + 4 x^{2}}

\frac{4}{1 + x^{2}}

ANSWER : 2

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