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যোগফল কত ?

2^{2} + 4^{2} + 6^{2} . . . . . . . . + (2 n)^{2} = ?

\frac{2}{3} n (n - 1) (n - 1)

\frac{2}{3} n (n + 1) (2 n + 1)

\frac{2}{3} n (n - 1) (2 n + 1)

\frac{2}{3} n (n - 1) (2 n - 1)

ANS : 2

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