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যদি

f : R \to R

f (x) = x^{2} + 1

f^{- 1} (0) =

f^{- 1} {0} = {i, - i}

f^{- 1} (0) = {\emptyset}

f^{- 1} (0) = \emptyset

কোনোটিই নয়

ANS : 1

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