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T = 2 π \sqrt{\frac{L}{g}}

T_{1} = 2 π \sqrt{\frac{{}^{L}1}{L_{2}}} \times T_{2}

T_{2} = T_{1} \times \sqrt{\frac{{}^{L}2}{L_{1}}}

L = \frac{g T^{2}}{4 π^{2}}

ANS : 2

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