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Question

2 (sinθcosθ + \sqrt{3}) = \sqrt{3} cosθ + 4 sinθ and 0 < θ < 360 ° then, θ = ?

30

°

, 150

°

90

°

, 0

°

60

°

, 120

°

45

°

, 135

°

None

ANS : 3

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