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e^{1 n (1 n x)}

হলে বক্ররেখাটির সমীকরণ-

y= 1nx (x-1) +3

y = x 1nx + 3

y = x(1nx-1) -3

y =x 1nx -3

y =x (1nx -1) +3

ANS : 5

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