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$f (x) = y = \sqrt{1 - x^{2}}; (0 \leq x \leq 1)$ হলে $f^{- 1} (x) = ?$

\sqrt{1 + y^{2}}

\sqrt{1 - y^{2}}

\sqrt{1 - x^{2}}

\sqrt{1 + x^{2}}

ANS : 3

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