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Question

$y = {(\frac{1}{\sqrt[n]{x}})}^{\frac{1}{x}}$ হলে $\frac{d y}{d x}$ এর মান কোনটি?

$\frac{y (\log x - 1)}{n}$

$3 y (\log x - 2)$

$\frac{(\log x - 3)}{y}$

$\frac{y (\log x - 1)}{x^{3}}$

$\frac{y (\log x - 1)}{n x^{2}}$

ANS : 5

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