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Question

$\frac{- 1}{2 x} - \frac{1}{4 y} + \frac{1}{x y} + \frac{1}{8} = ?$

$\frac{(x + 4) (2 - y)}{8 x y}$

$\frac{(x - 2) (y - 4)}{8 x y}$

$\frac{(x - 4) (y - 2)}{8 x y}$

$\frac{(x + 2) (4 - y)}{5 x y}$

ANS : 3

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