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Question
Sumi walks to her office at the rate of 4 miles per hour. If she increases her walking speed by 1 mile per hour , she would reach her office half an hour earlier than the previous time. What is the distance in miles of her office from her house ?
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<p><span style = "box - sizing: border - box; font - size: 18px; color: #212529; font - family: bangla, sans - serif; text - align: justify; background - color: #ffffff;">Let the distance and time be d mile and T hours respectively.</span></p> <p><span style = "box - sizing: border - box; font - size: 18px; color: #212529; font - family: bangla, sans - serif; text - align: justify; background - color: #ffffff;">So, d = 4T.</span></p> <p><span style = "box - sizing: border - box; font - size: 18px; color: #212529; font - family: bangla, sans - serif; text - align: justify; background - color: #ffffff;">Again, d = (4 + 1) (T - 1/2)</span></p> <p><span style = "box - sizing: border - box; font - size: 18px; color: #212529; font - family: bangla, sans - serif; text - align: justify; background - color: #ffffff;">or, 4T = 5(T - 1/2)</span></p> <p><span style = "box - sizing: border - box; font - size: 18px; color: #212529; font - family: bangla, sans - serif; text - align: justify; background - color: #ffffff;">or, 4T = 5T - 5/2</span></p> <p><span style = "box - sizing: border - box; font - size: 18px; color: #212529; font - family: bangla, sans - serif; text - align: justify; background - color: #ffffff;">or, 5T - 4T = 5/2</span></p> <p><span style = "box - sizing: border - box; font - size: 18px; color: #212529; font - family: bangla, sans - serif; text - align: justify; background - color: #ffffff;">or, T = 5/2 hours</span></p> <p><span style = "box - sizing: border - box; font - size: 18px; color: #212529; font - family: bangla, sans - serif; text - align: justify; background - color: #ffffff;">So, d = 4T = 4 x 5/2 = <strong>10 mile.</strong></span></p>
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