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Question

A train leaving Dhaka at 6am reaches Mymansing at 10 am and another train leaving Mymensing at 7 am and reaches Dhaka at 12 noon. At what time the two trains running opposite direction should meet?

7.40am

8.40am

9.20am

9.40am

10am

ANSWER : 2

Descrption

<p><span style = "color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;">Let , after t hours of Train A's strat(6.00 a.m) they will meet ,therefore Train B will run for( t - 1) Hour as it starts at 7.00 am.</span><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><span style = "color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;">Take distance  =  100</span><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><span style = "color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;">So, first train's speed  =  100/4  =  25kmph</span><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><span style = "color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;">Second train's speed  =  100 /5 =  20 kmph</span><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><span style = "color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;">We can built the equation based on distance covered by both train.</span><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><span style = "color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;">25*t   +   20(t - 1)  =  100</span><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><span style = "color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;">45*t =  120</span><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><span style = "color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;">t = 120/45</span><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><span style = "color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;">t = 8/3</span><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><span style = "color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;">So t hours  =  8/3  =  2hrs 40 minutes</span><br style = "outline: none; box - sizing: border - box; color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;" /><span style = "color: #222222; font - family: 'Open Sans', Arial, sans - serif; font - size: 13px; background - color: #ffffff;">Therefore they will meet at (6 am   +   2 hrs 40 min) = 8: 40 am</span></p>

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