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2^{2} + 4^{2} + 6^{2} + . . . . . . + (4 n)^{2} =

কত?

\frac{4}{3} n (2 n + 1) (4 n + 1)

\frac{3}{4} n (2 n + 1) (4 n + 1)

\frac{4}{3} (2 n + 1) (4 n + 1)

\frac{4}{3} n (2 n + 1)

ANS : 1

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